![]() Since line segment BA is used in both smaller right triangles, it is congruent to itself. Since line segment BA is an angle bisector, this makes ∠EBA ≅ ∠RBA. Now we have two small, right triangles where once we had one big, isosceles triangle: △BEA and △BAR. Where the angle bisector intersects base ER, label it Point A. Given that ∠BER ≅ ∠BRE, we must prove that BE ≅ BR.Īdd the angle bisector from ∠EBR down to base ER. To prove the converse, let's construct another isosceles triangle, △BER. Unless the bears bring honeypots to share with you, the converse is unlikely ever to happen. If I attract bears, then I will have honey. If I have honey, then I will attract bears. If I lie down and remain still, then I will see a bear.įor that converse statement to be true, sleeping in your bed would become a bizarre experience. If I see a bear, then I will lie down and remain still. If the premise is true, then the converse could be true or false: If the original conditional statement is false, then the converse will also be false. Now it makes sense, but is it true? Not every converse statement of a conditional statement is true. : heres my code for the same project.Converse Of the Isosceles Triangle Theorem If you are making an isosceles triangle with just a 80 degree corner and no 90, then you would first make the 9 inch side, then drag. Then you would drag the other two points until the side across from the 90 degree angle is 9 inches and the other two sides are equal. Joe? hehe I was absent last Friday and I guess I have until this Friday to finish this, but thanks anyway! Are you a regular poster here? Didn't know that. If it is a right isosceles triangle, you would first make the 90 degree angle. 'sets focus to the clear so the user can clear the non-numeric values If sidec ^ 2 = sidea ^ 2 + sideb ^ 2 ThenĮlse 'show the Enter Numeric Value label named lblWhat If sidec = sideb And sidea = sideb And sidea = sidec Then 'check to see if it is a Equiangular Triangle If side1 = side2 Or side2 = side3 Or side3 = side1 Then 'check to see if its an Isosceles triangle If side1 side2 And side2 side3 And side1 side3 Then If side1 = side2 And side2 = side3 And side1 = side3 Then 'check to see if its an equilateral triangle If side1 > side2 And side1 > side3 Then 'is side 1 th longest side?ĮlseIf side2 > side1 And side2 > side3 ThenĮlse 'side 3 is the longest side, so rename the sides this wat: 'declares the variables to ID the LONGEST side of the triangleĭim sidea As Single, sideb As Single, sidec As Single If IsNumeric(txtSide1) And IsNumeric(txtSide2) And IsNumeric(txtSide3) Thenĭim side1 As Single, side2 As Single, side3 As Single : : SideB = Side3 'No, then is Side 2 the longest side? : i don't understand those OR-Operations, since in a triangle it doesn't matter, which side it is, since you have the longest side. This is an isosceles right triangle, with the sides AB and AC equal and B measuring 90. Isosceles right triangle: In this triangle, one interior angle measures 90, and the other two angles measure 45 each. : : Else lblEnterNum.Visible = True 'If number isn't numeric, label displays to instruct user to enter a numeric value Broadly, right triangles can be categorized as: 1. : : lblIsNot.Visible = True 'If not, display the non-triangle label End If : : lblIs.Visible = True 'If all those equations are true, then display the IsTriangle label : : 'Defines the a, b, and c text boxes 'Test the three lengths to see if they form a triangle : : Else 'Side 3 is the longest side so rename the sides this way: : : ElseIf Side2 > Side1 And Side2 > Side3 Then 'Yes, rename the sides this way : : SideB = Side3 Or 2 'No, then is Side 2 the longest side? : : If Side1 > Side2 And Side1 > Side3 Then 'Is Side1 the longest side? : This message was edited by Barkeeper at 1:19:10 I've tried switching the variable names and the less than/greater than operators and nothing works anymore. Only stupidity of mankind and the universeĪre infinite, but i'm not sure concerning : SideB = Side3 'No, then is Side 2 the longest side? I don't understand those OR-Operations, since in a triangle it doesn't matter, which side it is, since you have the longest side. : Else lblEnterNum.Visible = True 'If number isn't numeric, label displays to instruct user to enter a numeric value : lblIsNot.Visible = True 'If not, display the non-triangle label End If : lblIs.Visible = True 'If all those equations are true, then display the IsTriangle label : 'Defines the a, b, and c text boxes 'Test the three lengths to see if they form a triangle : Else 'Side 3 is the longest side so rename the sides this way: : ElseIf Side2 > Side1 And Side2 > Side3 Then 'Yes, rename the sides this way : SideB = Side3 Or 2 'No, then is Side 2 the longest side? ![]() : If Side1 > Side2 And Side1 > Side3 Then 'Is Side1 the longest side? This message was edited by Barkeeper at 1:19:10
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